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How many grams of Al2O3, can be produced from 15 g of Al?rnrn 4 al + 3 o2 2 Al2O3
Accepted Answer
To answer this question, we need to find the mole ratio between Al and Al2O3.
The molar mass of Al is 26.98 g/mol and the molar mass of Al2O3 is 101.96 g/mol.
The balanced chemical equation is: 4 Al + 3 O2 -→ 2 Al2O3
The mole ratio of Al to Al2O3 is 4:2. This means that for every 4 moles of Al, 2 moles of Al2O3 are produced.
Now we can use the given mass of Al to calculate the grams of Al2O3 produced:
15 g Al * (1 mol Al / 26.98 g Al) = 0.556 mol Al
0.556 mol Al * (2 mol Al2O3 / 4 mol Al) = 0.278 mol Al2O3
0.278 mol Al2O3 * (101.96 g Al2O3 / 1 mol Al2O3) = 28.31 g Al2O3
Therefore, 15 g of Al can produce 28.31 g of Al2O3.
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