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How many grams of phosphoric acid is present in 0.5 m solution

Accepted Answer

Sure, here is a step-by-step calculation to determine the mass of phosphoric acid (H3PO4) present in 0.5 M solution:

1. Convert the molarity to moles per liter:

`0.5 M = 0.5 moles / liter`

2. Determine the number of moles of H3PO4 in 1 liter of solution:

`Moles of H3PO4 = Molarity x Volume of solution`

`Moles of H3PO4 = 0.5 moles / liter x 1 liter`

`Moles of H3PO4 = 0.5 moles`

3. Calculate the mass of H3PO4 using its molar mass:

`Molar mass of H3PO4 = 98.0 g/mol`

`Mass of H3PO4 = Moles of H3PO4 x Molar mass of H3PO4`

`Mass of H3PO4 = 0.5 moles x 98.0 g/mol`

`Mass of H3PO4 = 49.0 g`

Therefore, there are approximately 49.0 grams of phosphoric acid present in 0.5 M solution.

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