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How many grams of pure sodium hydroxide are needed for the preparation of 500 ml of 0.1000 n solution?

Accepted Answer

The equivalent weight of NaOH is 40 g/equivalent. The normality of the NaOH solution is 0.1000 N, which means that there are 0.1000 equivalents of NaOH per liter of solution. Therefore, the number of equivalents of NaOH needed to prepare 500 mL of 0.1000 N solution is: 0.1000 eq/L X 0.500 L = 0.0500 eq. The mass of NaOH needed to provide 0.0500 eq is: 0.0500 eq X 40 g/eq = 2.00 g. Therefore, 2.00 g of pure sodium hydroxide are needed for the preparation of 500 mL of 0.1000 N solution.

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