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I have Na2S2O3·5H2O. how to create a 5 ml of solution with a Na2S2O3 wt% = 61.48%
Accepted Answer
Materials:
- Na2S2O3·5H2O
- Analytical balance
- 5 mL volumetric flask
- Distilled water
Procedure:
1. Calculate the mass of Na2S2O3 required:
mass Na2S2O3 = (5 mL) * (1 g/mL) * (61.48% / 100%) = 0.3074 g
2. Weigh out 0.3074 g of Na2S2O3·5H2O on an analytical balance.
3. Transfer the weighed Na2S2O3·5H2O to a 5 mL volumetric flask.
4. Add distilled water to the flask until the volume reaches the 5 mL mark.
5. Stopper the flask and mix thoroughly by inverting it several times.
Your 5 mL solution of Na2S2O3 with a wt% of 61.48% is now ready for use.
- Na2S2O3·5H2O
- Analytical balance
- 5 mL volumetric flask
- Distilled water
Procedure:
1. Calculate the mass of Na2S2O3 required:
mass Na2S2O3 = (5 mL) * (1 g/mL) * (61.48% / 100%) = 0.3074 g
2. Weigh out 0.3074 g of Na2S2O3·5H2O on an analytical balance.
3. Transfer the weighed Na2S2O3·5H2O to a 5 mL volumetric flask.
4. Add distilled water to the flask until the volume reaches the 5 mL mark.
5. Stopper the flask and mix thoroughly by inverting it several times.
Your 5 mL solution of Na2S2O3 with a wt% of 61.48% is now ready for use.
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