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In a titration of 20 ml of 0.10 m NaOH with 0.20 m HCl, what will be the final volume of the solution when the sodium hydroxide is completely neutralized?
Accepted Answer
The final volume of the solution will be 30 mL. Here's why:
1. Reaction: NaOH (sodium hydroxide) reacts with HCl (hydrochloric acid) in a 1:1 mole ratio to form NaCl (sodium chloride) and H2O (water).
2. Moles of NaOH: (20 mL)
(0.10 mol/L) = 2 mmol NaOH
3. Moles of HCl needed: Since the reaction is 1:1, we need 2 mmol of HCl to neutralize the NaOH.
4. Volume of HCl: (2 mmol HCl) / (0.20 mol/L) = 10 mL HCl
5. Final Volume: (20 mL NaOH) + (10 mL HCl) = 30 mL
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