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Is Na[Co(SCN)4] tetrahedral?

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Yes, Na[Co(SCN)4] is likely tetrahedral. The complex anion [Co(SCN)4]- has a central cobalt(II) ion (Co2+) surrounded by four thiocyanate ligands (SCN-). The thiocyanate ligands act as monodentate ligands, coordinating to the cobalt ion through the nitrogen atom. The coordination number of the cobalt ion is four, which typically leads to a tetrahedral geometry.

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