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Liquid water has a density of 0.99970 g/ml at 10.0 c and 0.99565 g/ml at 30.0 c . Calculate the change in volume that occurs when 575 ml of water is heated from 10.0 c to 30.0 c .
Accepted Answer
Here's how to calculate the volume change:
1. Calculate the mass of the water:
Density at 10.0 °C: 0.99970 g/mL
Volume: 575 mL
Mass = Density x Volume = 0.99970 g/mL
575 mL = 574.83 g
2. Calculate the volume at 30.0 °C:
Density at 30.0 °C: 0.99565 g/mL
Mass: 574.83 g
Volume = Mass / Density = 574.83 g / 0.99565 g/mL = 577.58 mL
3. Calculate the change in volume:
Volume at 30.0 °C: 577.58 mL
Volume at 10.0 °C: 575 mL
Change in volume = 577.58 mL - 575 mL = 2.58 mL
Therefore, the volume of the water increases by 2.58 mL when heated from 10.0 °C to 30.0 °C.
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