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Liquid water has a density of 0.99970 g/ml at 10.0 c and 0.99565 g/ml at 30.0 c . Calculate the change in volume that occurs when 725 ml of water is heated from 10.0 c to 30.0 c .
Accepted Answer
Here's how to calculate the volume change:
1. Calculate the mass of the water:
- Use the density at 10.0 °C: mass = volume × density = 725 mL × 0.99970 g/mL = 724.78 g
2. Calculate the volume at 30.0 °C:
- Use the mass and the density at 30.0 °C: volume = mass / density = 724.78 g / 0.99565 g/mL = 728.43 mL
3. Calculate the change in volume:
- Change in volume = final volume - initial volume = 728.43 mL - 725 mL = 3.43 mL
Therefore, the volume of the water increases by approximately 3.43 mL when heated from 10.0 °C to 30.0 °C.
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