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Oxidation state of cobalt in [co(ox)3]^4-?

Accepted Answer

The oxidation state of cobalt in [Co(ox)3]^4- is +2. Here's why:

Oxalate (ox) Ligand: The oxalate ion (C2O4^2-) has a charge of -2.
Coordination Complex: The complex has a total charge of -4.
Charge Balance: Let x be the oxidation state of cobalt. We have the equation: x + 3(-2) = -4. Solving for x, we get x = +2.

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