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Reaction of formammide with a strong base
Accepted Answer
The reaction of formamide (HCONH2) with a strong base, such as sodium hydroxide (NaOH), is a hydrolysis reaction. The base deprotonates the amide, forming the formamide anion. This anion is then attacked by water, leading to the formation of formate (HCOO-) and ammonia (NH3). The overall reaction can be represented as:
HCONH2 + NaOH → HCOO- + NH3 + Na+ + H2O
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