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Reaction of METHYLFORMAMIDE with a strong base

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Methylformamide (HCONHCH3) reacts with a strong base like sodium hydroxide (NaOH) to form formate ion (HCOO-) and methylamine (CH3NH2). This is a nucleophilic acyl substitution reaction, where the base deprotonates the amide hydrogen, making the carbonyl carbon more susceptible to attack by the hydroxide ion. The resulting tetrahedral intermediate collapses, expelling the methylamine leaving group and forming the formate ion.

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