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Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the equationrnif you require 30.32 ml of 0.562 m NaOH solution to titrate 175.5 ml of rnh2so4 solution, what is the concentration of the H2SO4 solution?
Accepted Answer
Balanced chemical equation
H2SO4 + 2NaOH → Na2SO4 + 2H2O
Moles of NaOH used
Moles of NaOH = Molarity × Volume of NaOH
Moles of NaOH = 0.562 M × 0.03032 L = 0.01704 mol
Moles of H2SO4
From the balanced chemical equation, 1 mole of H2SO4 reacts with 2 moles of NaOH.
Moles of H2SO4 = 0.01704 mol NaOH × (1 mol H2SO4 / 2 mol NaOH) = 0.00852 mol
Concentration of H2SO4 solution
Concentration of H2SO4 = Moles of H2SO4 / Volume of H2SO4
Concentration of H2SO4 = 0.00852 mol / 0.1755 L = 0.0485 M
H2SO4 + 2NaOH → Na2SO4 + 2H2O
Moles of NaOH used
Moles of NaOH = Molarity × Volume of NaOH
Moles of NaOH = 0.562 M × 0.03032 L = 0.01704 mol
Moles of H2SO4
From the balanced chemical equation, 1 mole of H2SO4 reacts with 2 moles of NaOH.
Moles of H2SO4 = 0.01704 mol NaOH × (1 mol H2SO4 / 2 mol NaOH) = 0.00852 mol
Concentration of H2SO4 solution
Concentration of H2SO4 = Moles of H2SO4 / Volume of H2SO4
Concentration of H2SO4 = 0.00852 mol / 0.1755 L = 0.0485 M
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