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Suppose you are titrating vinegar, which is an acetic acid solution of unknown concentration, with a sodium hydroxide solution according to the equationrnrnif you require 32.81 ml of 0.1551 m NaOH solution to titrate 10.0 ml of HC2H3O2 solution, what is the molar concentration of acetic acid in the vinegar?
Accepted Answer
To determine the molar concentration of acetic acid in vinegar, we can use the following steps:
1. Write a balanced chemical equation for the titration reaction:
CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l)
2. Calculate the number of moles of NaOH used in the titration:
Moles of NaOH = Concentration of NaOH × Volume of NaOH
Moles of NaOH = 0.1551 M × 0.03281 L
Moles of NaOH = 0.005096 mol
3. According to the balanced chemical equation, 1 mole of CH3COOH reacts with 1 mole of NaOH. Therefore, the number of moles of CH3COOH in the vinegar sample is also 0.005096 mol.
4. Calculate the molar concentration of CH3COOH in the vinegar:
Molar concentration of CH3COOH = Moles of CH3COOH / Volume of CH3COOH
Molar concentration of CH3COOH = 0.005096 mol / 0.0100 L
Molar concentration of CH3COOH = 0.5096 M
Therefore, the molar concentration of acetic acid in the vinegar is 0.5096 M.
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