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The e (v) values for the two electrodes are shown: Fe3+ + e- Fe2+ e = +0.77 v, co 3+ + e- Co2+ e = +1.82 v. What is the EMF of the cell?rnrnoption ArnrnO 1.05 VrnrnOption BrnrnO-1.05 VrnrnOption Crnrn2.59 VrnrnOption DrnrnNone of the above

Accepted Answer

The EMF of the cell can be calculated using the formula: EMF = E°(cathode) - E°(anode) EMF = +1.82 V - (+0.77 V) = +1.05 V Therefore, the correct answer is Option A: 1.05 V


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