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What mass of sodium and chlorine in a 20.0g sample of sodium chloride? Name the scientist who providedrnexperimental evidence for this law.
Accepted Answer
Mass of Sodium and Chlorine in Sodium Chloride:
In a 20.0 g sample of sodium chloride (NaCl), the mass of sodium (Na) and chlorine (Cl) can be calculated as follows:
- Sodium (Na):
- Calculate the molar mass of NaCl: 22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol
- Use the molar mass to convert 20.0 g of NaCl to moles of NaCl: 20.0 g / 58.44 g/mol = 0.342 mol NaCl
- Since the mole ratio of Na to NaCl is 1:1, there are 0.342 mol of Na in the sample.
- Calculate the mass of Na: 0.342 mol Na x 22.99 g/mol Na = 7.83 g Na
- Chlorine (Cl):
- Use the mole ratio of Cl to NaCl (1:1) to calculate the moles of Cl in the sample: 0.342 mol NaCl
- Calculate the mass of Cl: 0.342 mol Cl x 35.45 g/mol Cl = 12.17 g Cl
Scientist who Provided Experimental Evidence for the Law of Definite Proportions:
Joseph Louis Proust proposed and provided experimental evidence for the Law of Definite Proportions in 1799. This law states that a chemical compound always contains the same elements in the same proportion by mass.
In a 20.0 g sample of sodium chloride (NaCl), the mass of sodium (Na) and chlorine (Cl) can be calculated as follows:
- Sodium (Na):
- Calculate the molar mass of NaCl: 22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol
- Use the molar mass to convert 20.0 g of NaCl to moles of NaCl: 20.0 g / 58.44 g/mol = 0.342 mol NaCl
- Since the mole ratio of Na to NaCl is 1:1, there are 0.342 mol of Na in the sample.
- Calculate the mass of Na: 0.342 mol Na x 22.99 g/mol Na = 7.83 g Na
- Chlorine (Cl):
- Use the mole ratio of Cl to NaCl (1:1) to calculate the moles of Cl in the sample: 0.342 mol NaCl
- Calculate the mass of Cl: 0.342 mol Cl x 35.45 g/mol Cl = 12.17 g Cl
Scientist who Provided Experimental Evidence for the Law of Definite Proportions:
Joseph Louis Proust proposed and provided experimental evidence for the Law of Definite Proportions in 1799. This law states that a chemical compound always contains the same elements in the same proportion by mass.
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