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What mass of solute in grams is required to make 273 millilitre of a 10.0% m/v solution

Accepted Answer

To make 273 milliliters of a 10.0 % (m/v) solution, you will need 27.3 grams of solute. This calculation is done using the formula: mass of solute = (percentage of solution / 100) * volume of solution. Plugging in our values, we get: mass of solute = (10.0 % / 100) * 273 mL = 27.3 grams.

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