Top topic this week
Back to FAQs
Related FAQs
Frequently Asked Question
Questions asked by users might not always be phrased in the clearest way.
What transition metal when coordinated with water to form an octahedral complex has the least intense peak: Ti, v, mn or ni
Accepted Answer
The transition metal that forms an octahedral complex with water and has the least intense peak is Ti (Titanium). Here's why:
d-electron configuration: The intensity of the color of a transition metal complex is related to the number of d-electrons and the possible electronic transitions. Ti(III) has only one d-electron, limiting the number of possible transitions and resulting in a pale color.
Ligand field splitting: Water is a weak-field ligand, which means it causes a relatively small splitting of the d-orbitals. This small splitting further reduces the energy difference between the d-orbitals, making the absorption of visible light less likely.
In comparison: V, Mn, and Ni all have more d-electrons and therefore exhibit more intense color due to the greater number of possible d-d transitions.
Articles you might like