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What would the balance equation be, for a reaction between sodium borohydride and benzil
Accepted Answer
The reaction of sodium borohydride (NaBH4) with benzil is a classic reduction reaction in organic chemistry. Here's the balanced equation:
C6H5COCOC6H5 + 2 NaBH4 + 4 H2O → 2 C6H5CHOHCHOHC6H5 + 2 NaBO2 + 4 H2
Explanation:
Benzil (C6H5COCOC6H5): The starting material with two ketone functional groups.
Sodium borohydride (NaBH4): A common reducing agent that provides hydride ions (H-) for reduction.
Water (H2O): Used to hydrolyze the intermediate boron species and to provide the necessary protons for the final product.
Hydrobenzoin (C6H5CHOHCHOHC6H5): The product, a diol, with two hydroxyl groups replacing the ketone groups.
Sodium metaborate (NaBO2): A byproduct of the reaction.
Hydrogen gas (H2): Also produced during the reaction.
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