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Which theoretical magnetic moment would calculate the magnetic moment for [co(ox)3]4-

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The theoretical magnetic moment for [Co(ox)3]4- can be calculated using the spin-only formula: μ = √n(n+2) BM, where n is the number of unpaired electrons. First, determine the oxidation state of cobalt: since oxalate (ox) has a -2 charge, and there are 3 of them, the overall charge of the complex is -6. To balance this, cobalt must have a +2 oxidation state. Co2+ has 3d7 electron configuration, which means there are 3 unpaired electrons. Plugging this into the formula, we get: μ = √3(3+2) BM = √15 BM ≈ 3.87 BM.

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