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You would use the spin-only magnetic moment formula to calculate the magnetic moment of [Co(ox)3]4-. This formula is: μ = √(n(n+2)) BM, where μ is the magnetic moment, n is the number of unpaired electrons, and BM is the Bohr magneton. To determine the number of unpaired electrons, you would need to consider the electronic configuration of the cobalt ion in the complex.