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Determine the number of moles of NaOH neutralized by 130 ml 0.230 m HNO3
Accepted Answer
The balanced chemical equation for the reaction is:
HNO₃(aq) + NaOH(aq) → NaNO₃(aq) + H₂O(l)
The mole ratio between HNO₃ and NaOH is 1:1. Therefore, the number of moles of NaOH neutralized is equal to the number of moles of HNO₃.
To calculate the number of moles of HNO₃, use the following formula:
moles = Molarity x Volume (in liters)
First, convert 130 mL to liters:
130 mL x (1 L / 1000 mL) = 0.130 L
Now, calculate the number of moles of HNO₃:
moles HNO₃ = 0.230 M x 0.130 L = 0.0299 moles
Therefore, 0.0299 moles of NaOH were neutralized.
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