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How is mole proportion of synthesis of tetrapotassium iminodisuccinate was performed in three steps: the first step involves the addition of 8 ml of water and 3.92 g of KOH sequentially to 4.6 g of maleic anhydride. second step: 3.16 g ammonium bicarbonate was added gradually stirring for 1 hour at 50°c. the last step: stirring for 0.5 hour at 110 c for the cyclization process.
Accepted Answer
The mole proportion of the synthesis of tetrapotassium iminodisuccinate can be determined by considering the stoichiometry of each step:
Step 1:
Maleic anhydride (C4H2O3): 4.6 g / 98.06 g/mol = 0.047 mol
KOH (potassium hydroxide): 3.92 g / 56.11 g/mol = 0.070 mol
Step 2:
Ammonium bicarbonate (NH4HCO3): 3.16 g / 79.06 g/mol = 0.040 mol
Step 3:
Cyclization involves the formation of the iminodisuccinate ring, but the mole proportion remains the same as in step 2.
Therefore, the mole proportions in the synthesis are approximately:
Maleic anhydride: 1
KOH: 1.5
Ammonium bicarbonate: 0.85
This information can be used to calculate the theoretical yield of the product and optimize the reaction conditions.
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