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If 1.58g of KMno4 is dissolved in 1dm3 of distilled water. Calculate its molarity
Accepted Answer
1. Calculate the number of moles of KMno4 present:
n(KMnO4) = mass(KMnO4) / molar mass(KMnO4)
molar mass(KMnO4) = 158.034 g/mol
n(KMnO4) = 1.58 g / 158.034 g/mol
n(KMnO4) = 0.01 mol
2. Calculate the volume of the solution in liters:
V(solution) = 1 dm^3 = 1 L
3. Calculate the molarity of the solution:
Molarity = moles of solute / volume of solution in liters
Molarity = 0.01 mol / 1 L
Molarity = 0.01 M
Therefore, the molarity of the solution is 0.01 M.
n(KMnO4) = mass(KMnO4) / molar mass(KMnO4)
molar mass(KMnO4) = 158.034 g/mol
n(KMnO4) = 1.58 g / 158.034 g/mol
n(KMnO4) = 0.01 mol
2. Calculate the volume of the solution in liters:
V(solution) = 1 dm^3 = 1 L
3. Calculate the molarity of the solution:
Molarity = moles of solute / volume of solution in liters
Molarity = 0.01 mol / 1 L
Molarity = 0.01 M
Therefore, the molarity of the solution is 0.01 M.
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