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Stoichiometry Problems Answer each of the following questions using the equation provided. be SURE to BALANCE EACH EQUATION BEFORE SOLVING ANY PROBLEMS. SHOW YOUR SOLUTION. 1. a g(s)+ h Cl(aq) MgCl 2 (aq)+ h 2 (g) a. How many grams of HCI are consumed by the reaction of 3.75 moles of magnesium? b. What is the mass in grams of h2 gas when 4.40 moles of HCI is added to the reaction?
Accepted Answer
The balanced chemical equation for the reaction of magnesium with hydrochloric acid is:
Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)
a. How many grams of HCl are consumed by the reaction of 3.75 moles of magnesium?
Step 1: Convert moles of Mg to moles of HCl using the mole ratio from the balanced equation:
3.75 moles Mg × (2 moles HCl / 1 mole Mg) = 7.50 moles HCl
Step 2: Convert moles of HCl to grams using the molar mass of HCl:
7.50 moles HCl × (36.46 g HCl / 1 mole HCl) = 273.45 g HCl
b. What is the mass in grams of H₂ gas when 4.40 moles of HCl is added to the reaction?
Step 1: Convert moles of HCl to moles of H₂ using the mole ratio from the balanced equation:
4.40 moles HCl × (1 mole H₂ / 2 moles HCl) = 2.20 moles H₂
Step 2: Convert moles of H₂ to grams using the molar mass of H₂:
2.20 moles H₂ × (2.016 g H₂ / 1 mole H₂) = 4.44 g H₂
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