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Here's how to solve the stoichiometry problem:
1. Balance the Equation:
The balanced equation is:
CaC2 + 2H2O → C2H2 + Ca(OH)2
2. Calculate the Mole Ratio:
The balanced equation shows that 1 mole of CaC2 reacts to produce 1 mole of Ca(OH)2.
3. Convert Moles of CaC2 to Moles of Ca(OH)2:
Since the mole ratio is 1:1, 4.25 moles of CaC2 will produce 4.25 moles of Ca(OH)2.
4. Convert Moles of Ca(OH)2 to Grams:
Find the molar mass of Ca(OH)2: Ca (40.08 g/mol) + 2
O (16.00 g/mol) + 2
H (1.01 g/mol) = 74.10 g/mol
Multiply the moles of Ca(OH)2 by its molar mass:
4.25 moles
74.10 g/mol = 315.43 g
Answer: 315.43 grams of Ca(OH)2 would be formed with 4.25 moles of CaC2.