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The balanced equation for the reaction is:
CaC2 + 2H2O → C2H2 + Ca(OH)2
From the balanced equation, we know that 1 mole of CaC2 reacts with 2 moles of H2O.
To find the grams of H2O needed for 4.25 moles of CaC2, we can use the following steps:
1. Convert moles of CaC2 to moles of H2O using the mole ratio from the balanced equation.
4.25 moles CaC2
(2 moles H2O / 1 mole CaC2) = 8.5 moles H2O
2. Convert moles of H2O to grams using the molar mass of H2O (18.015 g/mol).
8.5 moles H2O
(18.015 g H2O / 1 mole H2O) = 153.13 g H2O
Therefore, 153.13 grams of H2O are needed to react with 4.25 moles of CaC2.