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Both I and II are incorrect Lewis structures for BF3. Boron has three valence electrons, and fluorine has seven valence electrons. In a correct Lewis structure, boron will have three single bonds with fluorine atoms, and each fluorine atom will have three lone pairs of electrons. This arrangement satisfies the octet rule for fluorine but only has six electrons around boron. Therefore, BF3 is an exception to the octet rule. The correct Lewis structure would have three single bonds to the three fluorine atoms and no lone pairs on boron.