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The molar mass of BaCO3 is 197.33 g/mol. To calculate the mass in grams corresponding to 0.43 moles of BaCO3, we can use the formula: mass = moles × molar mass. Plugging in the values, we get: mass = 0.43 moles × 197.33 g/mol = 85.11 g. Therefore, 0.43 moles of BaCO3 correspond to 85.11 grams.