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Calculate the standard entropy of vaporization of water given that the standard enthalpy of vaporization is 41000j/mol and the boiling point of water is 100°c
Accepted Answer
The standard entropy of vaporization can be calculated using the following equation: ΔSvap = ΔHvap/Tb, where ΔSvap is the standard entropy of vaporization, ΔHvap is the standard enthalpy of vaporization, and Tb is the boiling point. Given that ΔHvap = 41000 J/mol, Tb=373K, ΔSvap = 41000J/mol / 373K = 109.92 J/(mol∙K). Therefore, the standard entropy of vaporization of water is 109.92 J/(mol∙K).
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