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Calculate the number of moles of cacl2 that can ne obtained from 15g of caco3 in the presence of excess HCL
Accepted Answer
1. Convert the mass of CaCO3 to moles using its molar mass (100.09 g/mol): 15 g CaCO3 * (1 mol CaCO3 / 100.09 g CaCO3) = 0.15 mol CaCO3
2. According to the balanced chemical equation, 1 mole of CaCO3 reacts with 2 moles of HCl. Therefore, 0.15 mol CaCO3 will react with 0.30 mol HCl.
3. Calculate the number of moles of CaCl2 that can be obtained using the mole ratio from the balanced chemical equation: 0.30 mol HCl * (1 mol CaCl2 / 2 mol HCl) = 0.15 mol CaCl2
Therefore, 15 g of CaCO3 will react with excess HCl to produce 0.15 mol of CaCl2.
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