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What volume of a 0.12 m KOH solution is needed to react with 23.ml of 0.22 m HCl?
Accepted Answer
Here's how to calculate the volume of KOH solution needed:
1. Write the balanced chemical equation:
KOH(aq) + HCl(aq) → KCl(aq) + H₂O(l)
2. Determine the moles of HCl:
moles HCl = (0.22 mol/L)
(23 mL)
(1 L/1000 mL) = 0.00506 mol
3. Use stoichiometry to find moles of KOH:
From the balanced equation, 1 mol KOH reacts with 1 mol HCl. Therefore, 0.00506 mol HCl will react with 0.00506 mol KOH.
4. Calculate the volume of KOH solution:
Volume KOH = (0.00506 mol) / (0.12 mol/L) = 0.0422 L
5. Convert to milliliters:
Volume KOH = 0.0422 L
(1000 mL/1 L) = 42.2 mL
Therefore, you need 42.2 mL of the 0.12 M KOH solution to react completely with 23 mL of 0.22 M HCl.
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