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What volume of rn gas will be produced if 60 l of ammonia, rn, is decomposed into rn and rn, assuming that all conditions are at STP?rnrnQuestion 3 options:rnrn90 Lrnrnrn120 Lrnrnrn150 Lrnrnrn30 Lrnrnrn60 l
Accepted Answer
The balanced chemical equation for the decomposition of ammonia is:
2NH3(g) → 3H2(g) + N2(g)
According to the stoichiometry of the reaction, 2 moles of NH3 will produce 3 moles of H2 and 1 mole of N2. Therefore, 60 L of NH3 will produce:
(60 L NH3) × (3 moles H2 / 2 moles NH3) × (22.4 L/mole H2) = 90 L H2
Hence, the volume of gas produced is 90 L.
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