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What volume of carbon dioxide is released during the combustion of 120 g of ethene?
Accepted Answer
The combustion of ethene (C2H4) with oxygen produces carbon dioxide (CO2) and water (H2O). Here's how to calculate the volume of CO2 released:
1. Balanced Chemical Equation:
C2H4 + 3O2 → 2CO2 + 2H2O
2. Moles of Ethene:
Molar mass of ethene (C2H4) = 28 g/mol
Moles of ethene = 120 g / 28 g/mol = 4.29 mol
3. Moles of Carbon Dioxide:
From the balanced equation, 1 mole of ethene produces 2 moles of CO2.
Moles of CO2 = 4.29 mol ethene
(2 mol CO2 / 1 mol ethene) = 8.57 mol CO2
4. Volume of Carbon Dioxide (at STP):
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 L.
Volume of CO2 = 8.57 mol
22.4 L/mol = 192 L
Therefore, approximately 192 liters of carbon dioxide are released during the combustion of 120 g of ethene at STP.
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