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Calculate the heat involved with 117 g HCl in the following reaction:rnsicl4 + 2h2o → SiO2 + 4hcl+ 67.3 kj.
Accepted Answer
The reaction shown is exothermic, releasing 67.3 kJ of heat for every 4 moles of HCl produced. To calculate the heat involved with 117 g of HCl, we need to follow these steps:
1. Convert grams of HCl to moles:
- Molar mass of HCl = 36.46 g/mol
- Moles of HCl = 117 g / 36.46 g/mol = 3.21 moles
2. Determine the heat released per mole of HCl:
- The reaction releases 67.3 kJ for 4 moles of HCl.
- Heat released per mole of HCl = 67.3 kJ / 4 moles = 16.83 kJ/mol
3. Calculate the total heat released:
- Total heat released = Heat released per mole
Moles of HCl
- Total heat released = 16.83 kJ/mol
3.21 moles = 54.0 kJ
Therefore, the heat involved with 117 g of HCl in the given reaction is 54.0 kJ.
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