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Calculate the heat involved with 196 g KBr (mw = 119 g/mol) in the following reaction:rn2kbr + H2SO4 + 120 kj → K2SO4 + 2hbr.
Accepted Answer
To calculate the heat involved, we need to determine the moles of KBr and use the stoichiometry of the reaction:
1. Moles of KBr:
Moles = mass / molar mass = 196 g / 119 g/mol = 1.65 mol KBr
2. Heat involved:
The reaction shows 120 kJ of heat is released for every 2 moles of KBr. Since we have 1.65 mol KBr, the heat involved is:
Heat = (120 kJ / 2 mol KBr)
1.65 mol KBr = 99 kJ
Therefore, 99 kJ of heat is involved in the reaction of 196 g KBr.
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