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Calculate the mass of silver chloride precipitated when an excess of aqueous sodium chloride is added to 1dm³ of 0.1/dm³ silver nitrate
Accepted Answer
Here's how to calculate the mass of silver chloride precipitated:
1. Write the balanced chemical equation:
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
2. Determine the moles of silver nitrate:
0.1 mol/dm³
1 dm³ = 0.1 mol AgNO₃
3. Use the stoichiometry of the reaction to find the moles of silver chloride:
The balanced equation shows a 1:1 mole ratio between AgNO₃ and AgCl. Therefore, 0.1 mol AgNO₃ will produce 0.1 mol AgCl.
4. Calculate the mass of silver chloride:
Mass = moles
molar mass
Mass = 0.1 mol
(107.87 g/mol Ag + 35.45 g/mol Cl)
Mass = 14.33 g AgCl
Therefore, 14.33 grams of silver chloride will precipitate.
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