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Calculate the mole fraction of water in solution that contains 128g of CH3OH and 108 in H2O explain how you go the mole of each component explain clearly

Accepted Answer

Here's how to calculate the mole fraction of water in the solution:
1. Calculate the moles of each component:

Moles of CH3OH:
- Molar mass of CH3OH = 12.01 g/mol (C) + 3(1.01 g/mol) (H) + 16.00 g/mol (O) = 32.04 g/mol
- Moles of CH3OH = (128 g) / (32.04 g/mol) = 4 mol

Moles of H2O:
- Molar mass of H2O = 2(1.01 g/mol) (H) + 16.00 g/mol (O) = 18.02 g/mol
- Moles of H2O = (108 g) / (18.02 g/mol) = 6 mol
2. Calculate the mole fraction of water (X_H2O):
- X_H2O = (moles of H2O) / (total moles of solution)
- X_H2O = 6 mol / (4 mol + 6 mol) = 0.6
Therefore, the mole fraction of water in the solution is 0.6.

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