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Calculate the number of moles of AlBr3 produced from 40.7 g of aluminum (al). The equation for the reaction is 2al(s)+3br2(l) = 2albr3(s)

Accepted Answer

Here's how to calculate the moles of AlBr3 produced:
1. Convert grams of Al to moles:
- Molar mass of Al = 26.98 g/mol
- Moles of Al = (40.7 g Al) / (26.98 g/mol) = 1.51 mol Al
2. Use the mole ratio from the balanced equation:
- The equation shows that 2 moles of Al react to produce 2 moles of AlBr3. This means the mole ratio is 2:2, or 1:1.
3. Calculate moles of AlBr3:
- Since the mole ratio is 1:1, 1.51 moles of Al will produce 1.51 moles of AlBr3.
Therefore, 40.7 g of aluminum will produce 1.51 moles of AlBr3.

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