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Calculate the oxidation number and the dn (or 3dn) configuration of the central metal ion in the following coordination complexes. an example is given below. Hint: You need to know the charges on the ligands. a. K[PtCl3NH3] b. Co(en)3Cl3 c. Na[FeCl4] d. [ninh3(cn)2f]no3
Accepted Answer
Here are the oxidation numbers and d-electron configurations for the central metal ions in the given coordination complexes:
a. K[PtCl3NH3]
Oxidation number of Pt: +2
d-electron configuration: d8
b. Co(en)3Cl3
Oxidation number of Co: +3
d-electron configuration: d6
c. Na[FeCl4]
Oxidation number of Fe: +3
d-electron configuration: d5
d. [NiNH3(CN)2F]NO3
Oxidation number of Ni: +2
d-electron configuration: d8
Explanation:
1. Charge Balance: The overall charge of the complex must equal zero. Use the known charges of the ligands to determine the oxidation number of the central metal ion.
2. Ligand Charges:
Cl: -1
NH3: 0
en (ethylenediamine): 0
CN: -1
F: -1
3. d-electron Configuration: The number of d-electrons in the metal ion is determined by its oxidation number and its position in the periodic table.
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