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Calculate the volume occupied by 7.43 g of oxygen gas (o2) at a pressure of 0.899 atm and a temperature of 25.0 c .
Accepted Answer
To calculate the volume, we can use the Ideal Gas Law: PV = nRT. Here's how we can solve it:
1. Convert mass to moles:
Molar mass of O2 = 32.00 g/mol
Moles of O2 = (7.43 g) / (32.00 g/mol) = 0.232 mol
2. Convert temperature to Kelvin:
Temperature in Kelvin = 25.0 °C + 273.15 = 298.15 K
3. Plug the values into the Ideal Gas Law:
(0.899 atm)
V = (0.232 mol)
(0.0821 L·atm/mol·K)
(298.15 K)
4. Solve for volume (V):
V = (0.232 mol
0.0821 L·atm/mol·K
298.15 K) / 0.899 atm
V ≈ 6.34 L
Therefore, the volume occupied by 7.43 g of oxygen gas under the given conditions is approximately 6.34 liters.
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